--description--
You can specify the lower and upper number of patterns with quantity specifiers using curly brackets. Sometimes you only want to specify the lower number of patterns with no upper limit.
To only specify the lower number of patterns, keep the first number followed by a comma.
For example, to match only the string hah
with the letter a
appearing at least 3
times, your regex would be /ha{3,}h/
.
let A4 = "haaaah";
let A2 = "haah";
let A100 = "h" + "a".repeat(100) + "h";
let multipleA = /ha{3,}h/;
multipleA.test(A4);
multipleA.test(A2);
multipleA.test(A100);
In order, the three test
calls would return true
, false
, and true
.
--instructions--
Change the regex haRegex
to match the word Hazzah
only when it has four or more letter z
's.
--hints--
Your regex should use curly brackets.
assert(haRegex.source.match(/{.*?}/).length > 0);
Your regex should not match the string Hazzah
haRegex.lastIndex = 0;
assert(!haRegex.test('Hazzah'));
Your regex should not match the string Hazzzah
haRegex.lastIndex = 0;
assert(!haRegex.test('Hazzzah'));
Your regex should match the string Hazzzzah
assert('Hazzzzah'.match(haRegex)[0].length === 8);
Your regex should match the string Hazzzzzah
assert('Hazzzzzah'.match(haRegex)[0].length === 9);
Your regex should match the string Hazzzzzzah
assert('Hazzzzzzah'.match(haRegex)[0].length === 10);
Your regex should match the string Hazzah
with 30 z
's in it.
assert('Hazzzzzzzzzzzzzzzzzzzzzzzzzzzzzzah'.match(haRegex)[0].length === 34);
--seed--
--seed-contents--
let haStr = "Hazzzzah";
let haRegex = /change/; // Change this line
let result = haRegex.test(haStr);
--solutions--
let haStr = "Hazzzzah";
let haRegex = /Haz{4,}ah/; // Change this line
let result = haRegex.test(haStr);